20x^2-5=21x

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Solution for 20x^2-5=21x equation:


Simplifying
20x2 + -5 = 21x

Reorder the terms:
-5 + 20x2 = 21x

Solving
-5 + 20x2 = 21x

Solving for variable 'x'.

Reorder the terms:
-5 + -21x + 20x2 = 21x + -21x

Combine like terms: 21x + -21x = 0
-5 + -21x + 20x2 = 0

Factor a trinomial.
(-1 + -5x)(5 + -4x) = 0

Subproblem 1

Set the factor '(-1 + -5x)' equal to zero and attempt to solve: Simplifying -1 + -5x = 0 Solving -1 + -5x = 0 Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -5x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -5x = 0 + 1 -5x = 0 + 1 Combine like terms: 0 + 1 = 1 -5x = 1 Divide each side by '-5'. x = -0.2 Simplifying x = -0.2

Subproblem 2

Set the factor '(5 + -4x)' equal to zero and attempt to solve: Simplifying 5 + -4x = 0 Solving 5 + -4x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -4x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -4x = 0 + -5 -4x = 0 + -5 Combine like terms: 0 + -5 = -5 -4x = -5 Divide each side by '-4'. x = 1.25 Simplifying x = 1.25

Solution

x = {-0.2, 1.25}

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